document.write( "Question 1184870: If nine men take 15 days to assemble 18 machines, how many days will it take 20 men to assemble 60 machines?\r
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document.write( "Clue: This problem is a combination of direct and indirect relations. To deal with this problem, ask yourself how the variable M(men) varies with the respected D(days); that I, will more men require more days or will more men require less days to do the job? How about M and C(machines)? Will more men produce more machines or more men produce less machines? \n" );
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Algebra.Com's Answer #815525 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 135 man days for 18 machines or 7.5 man days per machine. \n" ); document.write( "Therefore 60 machines need 450 man days with 20 men or 22.5 days. \n" ); document.write( "9*15/18=20*x/60 \n" ); document.write( "20x*18=60*9*15 \n" ); document.write( "360x=60*9*15 \n" ); document.write( "6x=135 \n" ); document.write( "x=22.5 days \n" ); document.write( "More men will require fewer days to do the same job, or more men will produce more machines, if time is held constant. \n" ); document.write( " |