document.write( "Question 1184866: A population mean is to be estimated from the sample described. Round your answer to one decimal place if necessary. Assume that all confidence intervals use a 95% confidence level.\r
\n" );
document.write( "\n" );
document.write( "Sample size = 3025, sample mean = 244, sample standard deviation = 80
\n" );
document.write( "What is the margin of error? \n" );
document.write( "
Algebra.Com's Answer #815524 by Boreal(15235) You can put this solution on YOUR website! the margin of error is t(0.975, df=3024) which is essentially 1.96, the z-value * 80/sqrt(3025)\r \n" ); document.write( "\n" ); document.write( "=1.96*80/55=2.85 is margin of error\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |