document.write( "Question 111672: Charles Miller invested his textbook royalty income in two accounts, one paying 3% annual simple interest and the other paying 2% interest. He earned a total of $11 interest. If he invested three times as much in the 3% account as he did in the 2% account, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #81552 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Interest (I)=Principal(P) times Rate(R) times Time(T) or I=PRT\r \n" ); document.write( "\n" ); document.write( "Let P=amount invested at 2% \n" ); document.write( "Then 3P=amount invested at 3%\r \n" ); document.write( "\n" ); document.write( "Interest at 2% for 1 year=P*0.02*1 \n" ); document.write( "Interest at 3% for 1 year=3P*0.03*1\r \n" ); document.write( "\n" ); document.write( "And we are told that the sum of the above interests =$11. So our equation to solve is:\r \n" ); document.write( "\n" ); document.write( "0.02P+3P*0.03=$11 simplify\r \n" ); document.write( "\n" ); document.write( "0.02P+0.09P=$11 collect like terms\r \n" ); document.write( "\n" ); document.write( "0.11P=$11 divide both sides by 0.11\r \n" ); document.write( "\n" ); document.write( "P=$100-----------------------amount invested at 2%\r \n" ); document.write( "\n" ); document.write( "3P=3*$100=$300-----------------------------amount invested at 3%\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "100*0.02+300*0.03=11 \n" ); document.write( "2+9=11 \n" ); document.write( "11=11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |