document.write( "Question 1184839: An arch is in the form of a semiellipse. It is 48 ft wide at the base and has a
\n" ); document.write( "height of 20ft. How wide is the arch at a height of 10 ft above the base?
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Algebra.Com's Answer #815485 by MathLover1(20849)\"\" \"About 
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\r
\n" ); document.write( "\n" ); document.write( "Here the length of the major axis is given as \"2a=48\" -> \"a=24\" and the height of the semi-ellipse is given as \"b=20\".\r
\n" ); document.write( "\n" ); document.write( "Now the standard equation of an ellipse with center at origin is:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Fa%5E2%2By%5E2%2Fb%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( "Putting the values of a and b in the above equation of an ellipse, we have\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F24%5E2+%2B+y%5E2%2F20%5E2+=+1\"\r
\n" ); document.write( "\n" ); document.write( "For the height of \"10\" feet, the equation becomes\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F576+%2B+10%5E2%2F400+=+1\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F576+%2B+100%2F400+=+1\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F576%2B1%2F4+=+1+\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F576+=+1+-1%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F576+=+3%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+%283%2F4%29576\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+3%2A144\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+sqrt%283%2A144%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+12sqrt%283%29+\" ft \r
\n" ); document.write( "\n" ); document.write( "at a height of \"10+\"ft above the base, the arch is \"+12sqrt%283%29+\" ft wide
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