document.write( "Question 1184678: A had some chocolate cookies and gave to B. A also had some strawberry cookies
\n" );
document.write( "and gave to B. A ate 32 chocolate cookies and B ate 14 strawberry cookies. B had
as many strawberry cookies are chocolate cookies left and A had
as many strawberry
\n" );
document.write( "cookies as chocolate cookies left. How many strawberry cookies did A have at first? \n" );
document.write( "
Algebra.Com's Answer #815480 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A had some chocolate cookies and gave \n" ); document.write( " A also had some strawberry cookies and gave \n" ); document.write( "let c = original number of Chocolate cookies \n" ); document.write( "let s = number of straw berries \n" ); document.write( "then \n" ); document.write( "A and B both have .5c and .5s \n" ); document.write( ": \n" ); document.write( " A ate 32 chocolate cookies and B ate 14 strawberry cookies. \n" ); document.write( "A then had: (.5c-32) and .5s, while B has: .5c and (.5s-14) \n" ); document.write( ": \n" ); document.write( " B had \n" ); document.write( ".5s-14 = \n" ); document.write( "get rid of the fraction, mult by 8, rearrange fractions for elimination \n" ); document.write( "8(.5s-14) = .5c \n" ); document.write( "4s - 112 - .5c = 0 \n" ); document.write( "4s -.5c = 112 \n" ); document.write( ": \n" ); document.write( "and A had \n" ); document.write( ".5s = \n" ); document.write( "multiply by 5 \n" ); document.write( "5(.5s) = .5c - 32 \n" ); document.write( " 2.5s - .5c = -32 \n" ); document.write( ": \n" ); document.write( "4s -.5c = 112 \n" ); document.write( "2.5s - .5c = -32 \n" ); document.write( "-------------------subtraction eliminates c, find s \n" ); document.write( "1.5s = 144 \n" ); document.write( "s = 144/1.5 \n" ); document.write( "s = 96 strawberry cookies A had at first \n" ); document.write( ":\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |