document.write( "Question 1184678: A had some chocolate cookies and gave \"1%2F2\" to B. A also had some strawberry cookies
\n" ); document.write( "and gave \"1%2F2\" to B. A ate 32 chocolate cookies and B ate 14 strawberry cookies. B had \"1%2F8\" as many strawberry cookies are chocolate cookies left and A had \"1%2F5\" as many strawberry
\n" ); document.write( "cookies as chocolate cookies left. How many strawberry cookies did A have at first?
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Algebra.Com's Answer #815480 by ankor@dixie-net.com(22740)\"\" \"About 
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A had some chocolate cookies and gave \"1%2F2\" to B.
\n" ); document.write( " A also had some strawberry cookies and gave \"1%2F2\" to B.
\n" ); document.write( "let c = original number of Chocolate cookies
\n" ); document.write( "let s = number of straw berries
\n" ); document.write( "then
\n" ); document.write( "A and B both have .5c and .5s
\n" ); document.write( ":
\n" ); document.write( " A ate 32 chocolate cookies and B ate 14 strawberry cookies.
\n" ); document.write( "A then had: (.5c-32) and .5s, while B has: .5c and (.5s-14)
\n" ); document.write( ":
\n" ); document.write( " B had \"1%2F8\" as many strawberry cookies as chocolate cookies left
\n" ); document.write( ".5s-14 = \"1%2F8\"(.5c)
\n" ); document.write( "get rid of the fraction, mult by 8, rearrange fractions for elimination
\n" ); document.write( "8(.5s-14) = .5c
\n" ); document.write( "4s - 112 - .5c = 0
\n" ); document.write( "4s -.5c = 112
\n" ); document.write( ":
\n" ); document.write( "and A had \"1%2F5\" as many strawberry cookies as chocolate cookies left.
\n" ); document.write( ".5s = \"1%2F5\"(.5c-32)
\n" ); document.write( "multiply by 5
\n" ); document.write( "5(.5s) = .5c - 32
\n" ); document.write( " 2.5s - .5c = -32
\n" ); document.write( ":
\n" ); document.write( "4s -.5c = 112
\n" ); document.write( "2.5s - .5c = -32
\n" ); document.write( "-------------------subtraction eliminates c, find s
\n" ); document.write( "1.5s = 144
\n" ); document.write( "s = 144/1.5
\n" ); document.write( "s = 96 strawberry cookies A had at first
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