document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1123342>Question 1123342</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the first n terms of a series is 5n^2-2n. The r-th term is...<BR>\n" );
document.write( "a) 6r+3         b) 10r-7         c) 4r^2-r       d) r(5r-2)      e)3r </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #815451 by </B><A HREF=/tutors/aboutme.mpl?userid=incline+dybala><B>incline dybala(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=incline+dybala><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=815451\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .\r<BR>\n" );
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document.write( "The r-th term is the difference between the first r terms and the sum of the first (r-1) terms, i.e.\r<BR>\n" );
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document.write( "a[r] = (5*r^2-2*r) - (5*(r-1)^2-2*(r-1)) = \r<BR>\n" );
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document.write( "           = 5r^2 - 2r - 5r^2 + 10r - 5 + 2r - 2 = 10r - 7.\r<BR>\n" );
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document.write( "Answer.  10r - 7.  Options b).\r<BR>\n" );
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document.write( "i got the answer from https://www.algebra.com/algebra/homework/word/misc/Miscellaneous_Word_Problems.faq.question.1123342.html\r<BR>\n" );
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document.write( " </SPAN>\n" );
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