document.write( "Question 1184797: Given that f(x) = 2x^2 - 8x + 1. Express 2x^2 - 8x + 1 in the form a(x+b)^2 + c,where a and b are integers. Find the coordinates of the stationary point on the graph of y = f(x). \n" ); document.write( "
Algebra.Com's Answer #815434 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "vertex is at ( \n" ); document.write( "\n" ); document.write( "the stationary point on the graph: \n" ); document.write( "The graph of a quadratic function (ie a parabola) only has a single stationary point. \n" ); document.write( "For an ‘up’ parabola this is the minimum; for a ‘down’ parabola it is the maximum (no need to talk about ‘local’ here) The \n" ); document.write( "\n" ); document.write( "so, the stationary point on the graph is \n" ); document.write( "\n" ); document.write( "or,\r \n" ); document.write( "\n" ); document.write( "The specific nature of a stationary point at x can in some cases be determined by examining the second derivative \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the stationary point on the graph is ( \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |