document.write( "Question 1184782: What is the value of k so that the function f(x) = (x-6)/(2x+k) will be its own inverse? \n" ); document.write( "
Algebra.Com's Answer #815428 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
\"x=%28y-6%29%2F%282y%2Bk%29\"-------just tried quickly switching x and y\r
\n" ); document.write( "\n" ); document.write( "\"%282y%2Bk%29x=y-6\"\r
\n" ); document.write( "\n" ); document.write( "\"2xy%2Bkx=y-6\"\r
\n" ); document.write( "\n" ); document.write( "\"2xy-y=-kx-6\"\r
\n" ); document.write( "\n" ); document.write( "\"y%282x-1%29=-kx-6\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-%28kx%2B6%29%2F%282x-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Want \"-%28kx%2B6%29%2F%282x-1%29=%28x-6%29%2F%282x%2Bk%29\"\r
\n" ); document.write( "\n" ); document.write( "\"-%28kx%2B6%29%282x%2Bk%29=%282x-1%29%28x-6%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%28-kx-6%29%282x%2Bk%29=%28x-6%29%282x-1%29\"\r
\n" ); document.write( "\n" ); document.write( "Looking at left and right members correspond, \"highlight%28k=-1%29\".
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