document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=111727>Question 111727</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For what values of k does the equation 2x squared + (1-k)x+8=0 have a double root?     I have tried numerous ideas, but cannot figure this out. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81542 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81542\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a double root means a perfect square\r<BR>\n" );
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document.write( "dividing by 2 gives x^2+((1-k)/2)x+4=0\r<BR>\n" );
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document.write( "taking the square roots of 4 leads us to (x+2)^2=x^2+4x+4 and (x-2)^2=x^2-4x+4\r<BR>\n" );
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document.write( "(1-k)/2=4 ___ 1-k=8\r<BR>\n" );
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document.write( "(1-k)/2=-4 ___ 1-k=-8 </SPAN>\n" );
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