document.write( "Question 1184757: The perimeter of a rectangle is 220 inches. The ratio of its length to its width is 7:3. Find the area of the rectangle. I need the answer in square inches. \n" ); document.write( "
Algebra.Com's Answer #815393 by ikleyn(52787)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "The length is 7x units long; the width is 3x units long.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The perimeter equation  2L + 2W = 220  takes the form\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    2*(7x) + 2*(3x) = 220,\r\n" );
document.write( "\r\n" );
document.write( "or\r\n" );
document.write( "\r\n" );
document.write( "    14x + 6x = 220,\r\n" );
document.write( "\r\n" );
document.write( "       20x   = 220\r\n" );
document.write( "\r\n" );
document.write( "         x   = 220/20 = 11 inches.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Therefore, the length is  7*11 = 77 inches;  the width is  3*11 = 33 inches\r\n" );
document.write( "\r\n" );
document.write( "and the area of the rectangle is  77*33 = 847  square inches.    ANSWER\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved and thoroughly explained.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );