document.write( "Question 1184757: The perimeter of a rectangle is 220 inches. The ratio of its length to its width is 7:3. Find the area of the rectangle. I need the answer in square inches. \n" ); document.write( "
Algebra.Com's Answer #815393 by ikleyn(52787)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "The length is 7x units long; the width is 3x units long.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The perimeter equation 2L + 2W = 220 takes the form\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 2*(7x) + 2*(3x) = 220,\r\n" ); document.write( "\r\n" ); document.write( "or\r\n" ); document.write( "\r\n" ); document.write( " 14x + 6x = 220,\r\n" ); document.write( "\r\n" ); document.write( " 20x = 220\r\n" ); document.write( "\r\n" ); document.write( " x = 220/20 = 11 inches.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Therefore, the length is 7*11 = 77 inches; the width is 3*11 = 33 inches\r\n" ); document.write( "\r\n" ); document.write( "and the area of the rectangle is 77*33 = 847 square inches. ANSWER\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved and thoroughly explained.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |