document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=111742>Question 111742</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system of equations by substitution:  y=x to the second power+2x-2<BR>\n" );
document.write( "                                                 y=3x+4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81535 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81535\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Y=X^2+2X-2 NOW SUBSTITUTE (X^2+2X-2) FOR Y IN THE SECOND EQUATION & SOLVE FOR X.<BR>\n" );
document.write( "X^2+2X-2=3X+4<BR>\n" );
document.write( "X^2+2X-3X-2-4=0<BR>\n" );
document.write( "X^2-X-6=0<BR>\n" );
document.write( "(X-3)(X+2)=0<BR>\n" );
document.write( "X-3=0<BR>\n" );
document.write( "X=3 ANSWER.<BR>\n" );
document.write( "X+2=0<BR>\n" );
document.write( "X=-2 ANSWER.<BR>\n" );
document.write( "Y=3*3+4<BR>\n" );
document.write( "Y=9+4<BR>\n" );
document.write( "Y=13 ANSWER.<BR>\n" );
document.write( "Y=3*-2+4<BR>\n" );
document.write( "Y=-6+4<BR>\n" );
document.write( "Y=-2 ANSWER. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );