document.write( "Question 1184710: A man invested part of P20,000 at 18% and the rest at 16%. The annual income from 16% investment was P620 less than three times the annual income from 18% investment. How much did he invest at 18%? \n" ); document.write( "

Algebra.Com's Answer #815348 by MathTherapy(10552) $\"\"$ $\"About$

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A man invested part of P20,000 at 18% and the rest at 16%. The annual income from 16% investment was P620 less than three times the annual income from 18% investment. How much did he invest at 18%?
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Let amount invested at 18% be E
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document.write( "Then amount invested at 16% = 20,000 - E
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document.write( "Income from 18% and 16% investments: .18E, and .16(20,000 - E), respectively
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document.write( "Based on what's given, we get: .16(20,000 - E) = 3(.18E) - 620
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document.write( "3,200 - .16E = .54E - 620
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document.write( "3,200 + 620 = .16E + .54E
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document.write( "3,820 = .7E
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document.write( "Amount invested at 18%, or  \n" );
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