document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1184688>Question 1184688</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the value if f(x)=5/x+2 and g(x)=-2x+3<BR>\n" );
document.write( "1.)f(-4)<BR>\n" );
document.write( "2.)g(1/2<BR>\n" );
document.write( "3.)g(-6)<BR>\n" );
document.write( "4.)f(m-2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #815319 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=815319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assuming f(x) = 5/(x+2) is what you intended...\r<BR>\n" );
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document.write( "1.) f(-4) = 5/ (-4+2) = 5/(-2) = -5/2, as a decimal that's -2.5<BR>\n" );
document.write( "2.) g(1/2) = -2(1/2) + 3 = ______<BR>\n" );
document.write( "and similar for the others, in #4, you need to plug in x=m-2  </SPAN>\n" );
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