document.write( "Question 1184673: Please help me solve this question
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document.write( "the fifth, ninth and sixteenth term of a linear sequence(a.p) are consecutive terms of an exponential sequence(g.p)
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document.write( "(i) find the common difference of the linear sequence in terms of the first terms
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document.write( "(ii) show that the twenty-first,thirty-seventh and sixty-fifth terms of the linear sequence are consecutive terms of an exponential sequence whose common ratio is 7/4 \n" );
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Algebra.Com's Answer #815305 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(i) 5th term of the ap: a+4d \n" ); document.write( "9th term: a+8d \n" ); document.write( "16th term: a+15d \n" ); document.write( "In a gp, the square of any term is equal to the product of the terms before and after it: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The problem is of little interest if d=0, so \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(i) ANSWER: d = (3/4)a \n" ); document.write( "(ii) 21st term: a+20d = a+15a = 16a \n" ); document.write( "37th term: a+36d = a+27a = 28a \n" ); document.write( "65th term: a+64d = a+48a = 49a \n" ); document.write( "28a/16a = 7/4; 49a/28a = 7/4; this sequence is geometric with common ratio 7/4 \n" ); document.write( " \n" ); document.write( " |