document.write( "Question 1184644: Solve the initial-value problem d^(2)y/dt^(2)+4dy/dt+4y=0,y(1)=0,y′(1)=1.\r
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Algebra.Com's Answer #815294 by robertb(5830)\"\" \"About 
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\n" ); document.write( "The characteristic equation of the D.E. is \"lambda%5E2+%2B+4%2Alambda+%2B+4+=+0\", which gives the double root \"lambda+=+-2\".\r
\n" ); document.write( "\n" ); document.write( "===> The general solution to the D.E. is \"y+=+A%2Ae%5E%28-2t%29+%2B+Bt%2Ae%5E%28-2t%29\".\r
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\n" ); document.write( "\n" ); document.write( "==> \"%22y%27%281%29%22+=+%28-2A%2BB%29e%5E%28-2%29+-+2Be%5E%28-2%29+=1\" ===> \"%28-2A-B%29e%5E%28-2%29+=+1\" ===> \"2A%2BB+=+-e%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "Also, \"y%281%29+=+Ae%5E%28-2%29+%2B+Be%5E%28-2%29+=+0\" ===> A + B = 0, or B = -A.\r
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\n" ); document.write( "\n" ); document.write( "Combining this with the preceding equation, we get \r
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\n" ); document.write( "\n" ); document.write( "\"2A+-+A+=+A+=+-e%5E2\". ===> \"B+=e%5E2\" ===> \"y+=+-e%5E2%2Ae%5E%28-2t%29+%2B+e%5E2%2At%2Ae%5E%28-2t%29\".\r
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\n" ); document.write( "\n" ); document.write( "after combining factors and simplifying, \"y%28t%29+=+%28t-1%29e%5E%28-2%28t-1%29%29\"\r
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