document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1184588>Question 1184588</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A store is having a sale on jelly beans and almonds. For 8 pounds of jelly beans and 4 pounds of almonds, the total cost is $33. For 3 pounds of jelly beans and 2 pounds of almonds, the total cost is $14. Find the cost for each pound of jelly beans and each pound of almonds. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #815226 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13215)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=815226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Informally, using logical reasoning....<br><BR>\n" );
document.write( "(1) Double the second purchase to 6 pounds of jelly beans and 4 pounds of almonds for $28.<BR>\n" );
document.write( "(2) Compare that to the first purchase of 8 pounds of jelly beans and 4 pounds of almonds for $33.<BR>\n" );
document.write( "(3) The difference is 2 more pounds of jelly beans for $5 more, so the cost of each pound of jelly beans is $2.50.<BR>\n" );
document.write( "(4) Plug that into either original purchase to find the cost of each pound of almonds is $3.25.<br><BR>\n" );
document.write( "The exact same calculations, using formal algebra....<br><BR>\n" );
document.write( "8j+4a=33 [1]<BR>\n" );
document.write( "3j+2a=14 [2]<br><BR>\n" );
document.write( "Double the second equation<br><BR>\n" );
document.write( "6j+4a=28 [3]<br><BR>\n" );
document.write( "Subtract [3] from [1]<br><BR>\n" );
document.write( "2j=5 [4]<BR>\n" );
document.write( "j=2.5<br><BR>\n" );
document.write( "Substitute j-2.5 in [1]<br><BR>\n" );
document.write( "8(2.5)+4a=33<BR>\n" );
document.write( "20+4a=33<BR>\n" );
document.write( "4a=13<BR>\n" );
document.write( "a=13/4=3.25<br><BR>\n" );
document.write( " </SPAN>\n" );
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