document.write( "Question 1184576: Sqrt125-sqrt80\r
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Algebra.Com's Answer #815202 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "    \"sqrt%28125%29\" = \"5%2Asqrt%285%29\".\r\n" );
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document.write( "    \"sqrt%2880%29\" = \"4%2Asqrt%285%29\".\r\n" );
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document.write( "    THEREFORE,  the difference  \"sqrt%28125%29\" - \"sqrt%2880%29\"  is equal to  \r\n" );
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document.write( "        \"5%2Asqrt%285%29\" - \"4%2Asqrt%285%29\" = \"1%2Asqrt%285%29\" = \"sqrt%285%29\".\r\n" );
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document.write( "    So, the identity in your post is correct, with x = 1.\r\n" );
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