document.write( "Question 1184546: A radio telescope has a parabolic dish with a diameter of 110 meters. The
\n" );
document.write( "collected radio signals are reflected to one connection point, called the focal point, being the focus of the parabola. If the focal length is 50 meters, find the depth of the dish, rounded to two decimal places. \n" );
document.write( "
Algebra.Com's Answer #815193 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "A radio telescope has a parabolic dish with a diameter of \n" ); document.write( "If the focal length is \n" ); document.write( "\n" ); document.write( "To simplify my computations, I'll put the vertex of my parabola (that is, the base of the dish) at the origin, so ( \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the focal length is \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This parabola extends forever in either direction, but I only care about the part of the curve that models the dish. Since the dish has a diameter of a \n" ); document.write( "\n" ); document.write( "The height of the edge of the dish (and thus the depth of the dish) will be the y-value of the equation at the \"ends\" of the modelling curve. The height of the parabola will be the same at either x-value, since they're each the same distance from the \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |