document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=111712>Question 111712</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A line passing through (–6, –5) and (–1, y) is perpendicular to a line with slope -5/13 .  Find the value of y. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81514 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81514\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE SLOPE OF A LINE PERPENDICULAR TO A LINE WITH A SLOPE OF -5/13 IS 13/5.<BR>\n" );
document.write( "THEREFORE THE SLOPE OF THE LINE THROUGH (-6,-5) & (-1,Y) IS:<BR>\n" );
document.write( "(Y+5)/(-1+6)=13/5<BR>\n" );
document.write( "(Y+5)/5=13/5 NOW CROSS MULTIPLY.<BR>\n" );
document.write( "5(Y+5)=5*13<BR>\n" );
document.write( "Y+5=13<BR>\n" );
document.write( "Y=13-5 <BR>\n" );
document.write( "Y=8 ANSWER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "(8+5)/5=13/5<BR>\n" );
document.write( "13/5=13/5\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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