document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1184506>Question 1184506</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For this problem A is the amount of salt in the tank.<BR>\n" );
document.write( "If a tank contains 250 liters of liquid with 11 grams of salt. A mixture containing 11 grams per liter is pumped into the tank at a rate of 5 liters/minute. The mixture is well-mixed, and pumped out at a rate of 6 liters/minute. The amount of salt in the tank satisfies the differential equation.\r<BR>\n" );
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document.write( "((6A)/(250-t))-55+A'=0 <BR>\n" );
document.write( "Rewriting this as a linear differential equation we get A'+((6A)/(250-t))=55\r<BR>\n" );
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document.write( "A)The integrating factor is <BR>\n" );
document.write( "B)And the solution is <BR>\n" );
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document.write( "(A)  The integrating factor is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=e%5E%286%2Aint%28dt%2F%28250-t%29%29%29+ ALIGN=MIDDLE  ALT=\"e%5E%286%2Aint%28dt%2F%28250-t%29%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=e%5E%28-6%2Aln%28250-t%29%29+=+%28250-t%29%5E%28-6%29 ALIGN=MIDDLE  ALT=\"e%5E%28-6%2Aln%28250-t%29%29+=+%28250-t%29%5E%28-6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "(B)   The solution is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%28t%29+=+11%28250+-+t%29+-+1.122x10%5E%28-11%29%2A%28250-t%29%5E6 ALIGN=MIDDLE  ALT=\"A%28t%29+=+11%28250+-+t%29+-+1.122x10%5E%28-11%29%2A%28250-t%29%5E6\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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