document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1184459>Question 1184459</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Gillian and Ben had a total of 4850 toys. Ben have 3/7 of his toys to Gillian. She then gave 1/3 of here toys to Ben. The ratio of the number of toys Gillian left to the number of toys Ben left was 2:3.<BR>\n" );
document.write( "a)  How many toys did Gillian have at the end?<BR>\n" );
document.write( "b)  How many toys did Ben have at first?\r<BR>\n" );
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document.write( "Dear teachers, can help me how to do this? Is ratio working backwards I think. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #815107 by </B><A HREF=/tutors/aboutme.mpl?userid=54929><B>54929(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=54929><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=54929><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=815107\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) Since the ratio of toys was 2:3, total toys are <BR>\n" );
document.write( "4850<BR>\n" );
document.write( "Hence 4850 * 2/2+3 = 1940<BR>\n" );
document.write( " the answer is 1940 toys\r<BR>\n" );
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document.write( " b) Assuming Ben had x toys at first<BR>\n" );
document.write( " Gillian had y toys at first <BR>\n" );
document.write( " { (1-3/7)x + 1/3(3/7x + y) = 4850 * 3/5<BR>\n" );
document.write( " { (3/7x + y) (1 - 1/3) = 1940\r<BR>\n" );
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document.write( " { 5/7x + 1/3y = 2910 => { x = 3395<BR>\n" );
document.write( " { 2/7x + 2/3y = 1940      { y = 1455<BR>\n" );
document.write( " Ben had 3395 toys. </SPAN>\n" );
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