document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1184054>Question 1184054</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ken had 1 1/2 times as many bookmarks as Lionel. Mike had 3/4 as many bookmarks as <BR>\n" );
document.write( "Ken. Ken and Lionel gave Mike a number of bookmarks in the ratio 3:1. As a result, Mike <BR>\n" );
document.write( "had twice as many bookmarks as before, and Lionel had 32 bookmarks more than Ken. <BR>\n" );
document.write( "How many bookmarks did Ken give to Mike?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #815106 by </B><A HREF=/tutors/aboutme.mpl?userid=54929><B>54929(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=54929><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=54929><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=815106\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To calculate the number of bookmarks that Ken gave to Mike.\r<BR>\n" );
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document.write( "Let consider x to be the number of Lionel's bookmark. According to question, we have<BR>\n" );
document.write( "Bookmarks of Ken = 1 1/2 * Bookmarks of Lionel<BR>\n" );
document.write( "Bookmarks of Ken = 1.5x\r<BR>\n" );
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document.write( "Bookmarks of Mike = (3/4) * Bookmarks of Ken\r<BR>\n" );
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document.write( "Bookmarks of Mike = (3/4) * (1.5x)\r<BR>\n" );
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document.write( "Bookmarks of Mike = 1.125x\r<BR>\n" );
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document.write( "If Ken give 3y bookmarks to Mike then Lionel gives 1y bookmarks to Mike. The total number of bookmarks each of one have now is given by,\r<BR>\n" );
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document.write( "Bookmarks of Ken = 1.5x - 3y\r<BR>\n" );
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document.write( "Bookmarks of Mike = 1.125x + 4y\r<BR>\n" );
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document.write( "Bookmarks of Lionel = x - y\r<BR>\n" );
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document.write( "Bookmarks of Mike now = 2(Previous bookmarks of Mike)\r<BR>\n" );
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document.write( "⇒ 1.125x + 4y = 2(1.125x)\r<BR>\n" );
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document.write( "Bookmarks of Lionel = Bookmarks of Ken + 32<BR>\n" );
document.write( "⇒ x - y = 1.5x - 3y + 32\r<BR>\n" );
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document.write( "On solving both the equations, we get<BR>\n" );
document.write( "x = 512<BR>\n" );
document.write( "y = 144\r<BR>\n" );
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document.write( "Thus, the Ken gave 3(144) =<BR>\n" );
document.write( "432<BR>\n" );
document.write( "bookmarks to the Mike.\r<BR>\n" );
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