document.write( "Question 1184465: A box contains 20 balls out which 7 are white balls, 5 are black balls, 6 are
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document.write( "red balls and 2 are yellow balls. If four balls are drawn at random. What is
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document.write( "the probability that balls of one colour, balls of two colours and balls of three colours are drawn? \n" );
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Algebra.Com's Answer #815105 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! there are 20C4 ways to draw 4 balls=4845 \n" ); document.write( "one color \n" ); document.write( "white is 7C4/20C4=35/4845 and may be reduced. \n" ); document.write( "black is 5C4/20C4=5/4845 \n" ); document.write( "red is 6C4/20C4=15/4845 \n" ); document.write( "yellow is 0 since there must be at least 4 of them. \n" ); document.write( "balls of 1 color has probability of 55/4845 of being drawn \n" ); document.write( "-- \n" ); document.write( "two colors would be \n" ); document.write( "(same denominator or 4845) \n" ); document.write( "white black \n" ); document.write( "7C1*5C3+7C2*5C2+7C3*5C1=70+210=175=455 \n" ); document.write( "- \n" ); document.write( "white red \n" ); document.write( "7C1*6C3+7C2+6C2+7C3*6C1=140+315+210=665 \n" ); document.write( "- \n" ); document.write( "white-yellow \n" ); document.write( "7C2*2C2+7C3+2C1=21+70=91 \n" ); document.write( "- \n" ); document.write( "black-red \n" ); document.write( "5C1*6C3+5C2*6C2+5C3*6C1=100+150+60=310 \n" ); document.write( "- \n" ); document.write( "black-yellow \n" ); document.write( "5C2*2C2+5C3*2C1=30 \n" ); document.write( "- \n" ); document.write( "red-yellow \n" ); document.write( "6C2*2C2+6C3*2C1=55 \n" ); document.write( "Total for these is 1606/4845 \n" ); document.write( "----- \n" ); document.write( "w-b-r \n" ); document.write( "7C2*5C1*6C1+7C1*5C2*6C1+7C1*5C1*6C2=630+420+525=1575 \n" ); document.write( "w-b-y \n" ); document.write( "7C2*5C1*2C1+7C1*5C2*2C1+7C1*5C1*2C2=210+140+35=385 \n" ); document.write( "- \n" ); document.write( "w-r-y \n" ); document.write( "7C2*6C1*2C1+7C1*6C2*2C1+7C1*6C1*2C2=252+210+42=504 \n" ); document.write( "- \n" ); document.write( "b-r-y \n" ); document.write( "5C2*6C1*2C1+5C1*6C2*2C1+5C1*6C1*2C2=120+150+30=300 \n" ); document.write( "That total is 2764/4845 \n" ); document.write( "- \n" ); document.write( "Not asked for but balls of 4 colors would be 7C2*5C1*6C1*2C1=420/4845\r \n" ); document.write( "\n" ); document.write( "55+1606+2764+420=4845, and that accounts for all the possibilities. \n" ); document.write( " |