document.write( "Question 16653: Two numbers, which differ by 3, have a product of 88. Find them by forming a quadratic equation. \n" ); document.write( "

Algebra.Com's Answer #8151 by rahman(247) $\"\"$ $\"About$

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Suppose: x is the first number and y is the second number.
\n" ); document.write( "Math Models:
\n" ); document.write( "x - y = 3 ----------->y=x-3 .........(i)
\n" ); document.write( "xy=88 .......(ii)\r
\n" ); document.write( "\n" ); document.write( "Substitute (i) to (ii)
\n" ); document.write( "xy=88
\n" ); document.write( "x(x-3)=88
\n" ); document.write( " $\"x%5E2-3x=88\"$
\n" ); document.write( " $\"x%5E2-3x-88=0\"$
\n" ); document.write( "(x+8)(x-11)=0
\n" ); document.write( "x+8=0 or x-11=0
\n" ); document.write( "x=-8 or x=11
\n" ); document.write( "-----------------------
\n" ); document.write( "Substitute x=-8 to (i)
\n" ); document.write( "y=x-3
\n" ); document.write( "y=-8-3=-11
\n" ); document.write( "-----------------------
\n" ); document.write( "Substitute x=11 to (i)
\n" ); document.write( "y=x-3
\n" ); document.write( "y=11-3=8
\n" ); document.write( "-----------------------
\n" ); document.write( "Thus, x=-8 and y=-11 or x=11 and y=8 \n" ); document.write( "

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