document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1184466>Question 1184466</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the sum of the series 1 + 1/3 + 1.3/3.6 + 1.3.5/3.6.9 + 1.3.5.7/3.6.9.12 + .... ?<BR>\n" );
document.write( "[Note: Here . means product and / means division] </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #815059 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52787)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=815059\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .\r<BR>\n" );
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document.write( "To see the solution/solutions, look into these open sources\r<BR>\n" );
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document.write( "https://tardigrade.in/question/the-sum-of-the-infinite-series-1-1-3-1-3-3-6-1-35-3-6-9-1-3-lat2aerj\r<BR>\n" );
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document.write( "https://byjus.com/jee-questions/the-value-of-1-plus-1-by-3-plus-1-3-by-3-6-is-equal-to/\r<BR>\n" );
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