document.write( "Question 2032: In a case of a quadratic equation, why are there two x-intercepts and one y-intercept?
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Algebra.Com's Answer #815 by khwang(438)\"\" \"About 
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If a given quadratic equation as:\r
\n" ); document.write( "\n" ); document.write( " y = ax^2 +b x + c. (Note a <> 0,& b,c reals)\r
\n" ); document.write( "\n" ); document.write( " To find x-intercept,since the corresponding point which y-coordinate
\n" ); document.write( " must be 0. We have to solve the equation\r
\n" ); document.write( "\n" ); document.write( " y = ax^2 +b x + c = 0...(*).
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\n" ); document.write( " In general,if the discriminant b^2 - 4ac > 0, (*) has two different
\n" ); document.write( " real roots and hence there are two x-intercepts
\n" ); document.write( " (-b+sqrt(b^2 - 4ac))/2a or (-b-sqrt(b^2 - 4ac))/2a if b^2 - 4ac > 0.\r
\n" ); document.write( "\n" ); document.write( " [Note: IF b^2 - 4ac = 0 , there is only one x-intercept -b/2a
\n" ); document.write( " IF b^2 - 4ac < 0 , there are no x-intercepts ]\r
\n" ); document.write( "\n" ); document.write( " To find y-intercept,since the corresponding point which x-coordinate
\n" ); document.write( " must be 0. When we set x =0, we obtain
\n" ); document.write( " y = c. Hence, there is only one y-intercept c.\r
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\n" ); document.write( "\n" ); document.write( " Kenny\r
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