document.write( "Question 1184358: Verify that the obtained function is smooth at all points in your domain:
\n" ); document.write( "f(x)={ 2 , if 0≤x≤2.72
\n" ); document.write( "-----{ln(x^2),if 2.72< x < 20 \r
\n" ); document.write( "\n" ); document.write( "-------{ x-14 , if 20≤x≤25
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Algebra.Com's Answer #814981 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "No, your function is not smooth in the domain [0, 25]. In fact, it's not even continuous.\r
\n" ); document.write( "\n" ); document.write( "What makes it continuous is the following definition: \r
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\n" ); document.write( "\n" ); document.write( "But even with the correct definition it still is not smooth, as the function is not differentiable at \"x+=+e\" and \"x+=+e%5E3\" \r
\n" ); document.write( "\n" ); document.write( "At \"x+=+e\", the left-hand derivative is \"%22f%27%22%5Bl%5D+%28e%29=0\", while the right-hand derivative is \"%22f%27%22%5Br%5D+%28e%29=2%2Fe\", so the derivative at \"x=e\"does not exist.\r
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\n" ); document.write( "\n" ); document.write( "At \"x+=+e%5E3\", the left-hand derivative is \"%22f%27%22%5Bl%5D+%28e%5E3%29=2%2Fe%5E3\", while the right-hand derivative is \"%22f%27%22%5Br%5D+%28e%5E3%29+=+0\", so the derivative at \"x=e%5E3\"does not exist.
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