document.write( "Question 1184410: Gab’s age on his birthday in 1989 is equal to the sum of the digits of the year 19xy in which he was born. If x and y satisfies the equation x - y - 6 = 0, find the age of Gab in 1990. \n" ); document.write( "
Algebra.Com's Answer #814979 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "x-y-6=0 ==> x = y+6 \n" ); document.write( "Since x and y are both single-digit integers, there are only a few possibilities. Solving the problem by trial and error is probably easier than solving it using formal algebra. \n" ); document.write( "y=0, x=6 ==> he was born in 1960; his age in 1989 was 29; 1+9+6+0 is not equal to 29. Doesn't work. \n" ); document.write( "y=1, x=7 ==> he was born in 1971; his age in 1989 was 18; 1+9+7+1 = 18. It works! \n" ); document.write( "So Gabe was born in 1971. \n" ); document.write( "ANSWER: Gabe's age in 1990 was 1990-1971 = 19 \n" ); document.write( "It turns out that a solution using formal algebra is relatively easy.... \n" ); document.write( "His age in 1989 is the difference between 89 and \"xy\", which algebraically is \n" ); document.write( " \n" ); document.write( "His age in 1989 is equal to the sum of the digits of the year in which he was born: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Given the restriction that x and y are both single digit positive integers, the only solution to that equation is x=7 and y=1. \n" ); document.write( "Of course you could finish that last step still using formal algebra, knowing that x=y+6: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So again (of course!) we find he was born in 1971, which means his age in 1990 was 19. \n" ); document.write( " \n" ); document.write( " |