document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1184391>Question 1184391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tim and Ron have some sweets each. If Tim eat 8 has of his sweets,  the ratio of the number of sweets Tim has to the number of sweets Ron has becomes have 2:7. If Ron eats 8 of his sweets, Tim will have 80% as many sweets as Ron. How many sweets do they have altogether? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #814962 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=814962\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (T-8)/R=2/7<BR>\n" );
document.write( "T/(R-8)=4/5<BR>\n" );
document.write( "cross-multiply each<BR>\n" );
document.write( "2R=7T-56<BR>\n" );
document.write( "4R-32=5T<BR>\n" );
document.write( "rewrite<BR>\n" );
document.write( "2R-7T=-56<BR>\n" );
document.write( "4R-5T=32<BR>\n" );
document.write( "-4R+14T=+112, multiplying top by -2<BR>\n" );
document.write( "so 9T=144<BR>\n" );
document.write( "T=16 for Tim<BR>\n" );
document.write( "8/R=2/7<BR>\n" );
document.write( "2R=56<BR>\n" );
document.write( "R=28 for Ron<BR>\n" );
document.write( "Tim has 16, Ron has 28<BR>\n" );
document.write( "Together they have 44 ANSWER\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );