document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1184332>Question 1184332</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A hospital needed supplies of an expensive medicine company a has the most supplies available 1.4 mg which  is twice the difference between the weight of company b supplies and c company and  0.8 mg more than company c  supplies how many milligrams can the hospital get from these three companies </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #814937 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=814937\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = 1.4 mg.<BR>\n" );
document.write( "A = 2 * abs(B - C)<BR>\n" );
document.write( "A = C + .8\r<BR>\n" );
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document.write( "from A = C + .8, you get:<BR>\n" );
document.write( "1.4 = C + .8<BR>\n" );
document.write( "subtract .8 from both sides of that equation to get:<BR>\n" );
document.write( "1.4 - .8 = C<BR>\n" );
document.write( "solve for C to get:<BR>\n" );
document.write( "C = .6\r<BR>\n" );
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document.write( "from A = 2 * (B - C),  you get:<BR>\n" );
document.write( "1.4 = 2 * (B - .6)<BR>\n" );
document.write( "simplify to get:<BR>\n" );
document.write( "1.4 = 2 * B - 1.2<BR>\n" );
document.write( "add 1.2 to both sides of the equation to get:<BR>\n" );
document.write( "1.4 + 1.2 = 2 * B<BR>\n" );
document.write( "combine like terms to get:<BR>\n" );
document.write( "2.6 = 2 * B<BR>\n" );
document.write( "solve for B to get:<BR>\n" );
document.write( "B = 1.3\r<BR>\n" );
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document.write( "your solution should be A + B + C = 1.4 + 1.3 + .6 = 3.3 mg.\r<BR>\n" );
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document.write( "to confirm the numbers are good:\r<BR>\n" );
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document.write( "A = 1.4, B = 1.3, C = .6<BR>\n" );
document.write( "A = 2 * (B - C) becomes:<BR>\n" );
document.write( "A = 2 * (1.3 - .6) which becomes:<BR>\n" );
document.write( "A = 2 * (.7) which becomes:<BR>\n" );
document.write( "A = 1.4 which is true.\r<BR>\n" );
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document.write( "A = 1.4, C = .6<BR>\n" );
document.write( "A = C + .8 becomes:<BR>\n" );
document.write( "A = .6 + .8 which becomes:<BR>\n" );
document.write( "A = 1.4 which is true.\r<BR>\n" );
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document.write( "all original statements are true when A = 1.4 and B = 1.3 and C = .6<BR>\n" );
document.write( "this confirms the numbers are correct.<BR>\n" );
document.write( "the solution is the sum of those numbers = 3.3.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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