document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1184345>Question 1184345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Insert the indicated number of arithmetic means given the first and last term, show the solution\r<BR>\n" );
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document.write( "3 and 36 <BR>\n" );
document.write( "Indicated 7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #814929 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=814929\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "When n arithmetic means are inserted between a and b, b is equal to a plus (n+1) times the common difference.  So in this problem<br><BR>\n" );
document.write( "36 = 3+(7+1)d<BR>\n" );
document.write( "36 = 3+8d<BR>\n" );
document.write( "8d=33<BR>\n" );
document.write( "d=33/8 or 4 1/8<br><BR>\n" );
document.write( "The sequence is<br><BR>\n" );
document.write( "3, 7 1/8, 11 1/4, ..., 31 7/8, 36<br><BR>\n" );
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