document.write( "Question 1184368: What are the foci of the hyperbola with the equation y²/12-x²/5 = 1 \n" ); document.write( "

Algebra.Com's Answer #814927 by ikleyn(52803) $\"\"$ $\"About$

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document.write( "From the given equation of the hyperbola, you have these two equations for its semi-axis \"a\"  and  \"b\"\r\n" );
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document.write( "    a^2 = 12;  b^2 = 5.\r\n" );
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document.write( "The hyperbola is open vertically up and down.  The transverse axis is vertical y-axis; the imaginary axis is horizontal x-axis.\r\n" );
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document.write( "Vertical semi-axis (transverse) is  a = .\r\n" );
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document.write( "The vertices of the hyperbola are the point  (,)  and  (,)  on y-axis.\r\n" );
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document.write( "For the half the distance \"c\" between the foci we have this equation\r\n" );
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document.write( "    c =  =  =  = 4.1231 (rounded).\r\n" );
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document.write( "The foci are these points  F1 = (,)  and  (,)  on y-axis.\r\n" );
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\n" ); document.write( "\n" ); document.write( "On hyperbola canonical equation see the lesson\r
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