document.write( "Question 16720: Please help me with the following:\r
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document.write( "Find the indicated difference quotient and simplify answer:\r
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document.write( "Given f(x) = 5x + 3 \r
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document.write( "find f(x) f(2) over x-2\r
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document.write( "what I tried:
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document.write( "1. f(x) = 5x+3
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document.write( "2. f(x) - f(2) = 5x + 3 - 5x + 3(2) = 9
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document.write( "3. f(x) - f(2) over x-2 = 9 over 5x + 3-2 = 9 over 5x + 1\r
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document.write( "Unfortunately this does not come close to the teacher's answer of 5.
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document.write( "Can you please tell me what I'm doing wrong?\r
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document.write( "Thanks
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document.write( "Sandy \n" );
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Algebra.Com's Answer #8149 by bam878s(77)![]() ![]() ![]() You can put this solution on YOUR website! we know f(x) = 5x + 3 \n" ); document.write( "also, f(2) = 5(2) + 3 = 13 \n" ); document.write( "f(x) - f(2) = 5x + 3 - 13 = 5x -10\r \n" ); document.write( "\n" ); document.write( "now \n" ); document.write( "now cancel x - 2 in both the numberator and denominator to get 5. \n" ); document.write( "Hope this helps Sandy. \n" ); document.write( " |