document.write( "Question 1184308: Given that the equation px^2 + 3px + p + q = 0,where p is not = 0, has two equal real roots,find q in terms of p \n" ); document.write( "
Algebra.Com's Answer #814897 by robertb(5830)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If \"px%5E2+%2B+3px+%2B+p+%2B+q+=+0\" has two equal roots, then the left -hand side can be written as \"p%28x+-+alpha%29%5E2+=+0\", where \"alpha\" is the real double root.\r
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\n" ); document.write( "\n" ); document.write( "===> \r
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\n" ); document.write( "\n" ); document.write( "===> \"3p+=+-2p%2Aalpha\" and \"p+%2B+q+=+p%2Aalpha%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "The first equation implies that \"alpha+=+-3%2F2\".\r
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\n" ); document.write( "\n" ); document.write( "===> \"p+%2B+q+=+%289%2F4%29p\" ===> \"q+=+%285%2F4%29p\"
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