document.write( "Question 1184274: An epidemiologist is worried about the ever increasing trend of malaria in a certain locality
\n" ); document.write( "and wants to estimate the proportion of people infected in the peak malaria transmission
\n" ); document.write( "period. If he takes a random sample of 150 people in that locality during the peak
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\n" ); document.write( "i. 99% confidence interval for the proportion of the whole infected people in that
\n" ); document.write( "locality during the peak malaria transmission period.
\n" ); document.write( "ii. Based on your results in part (i), do you think the epidemiologist’s worry is
\n" ); document.write( "justified? Explain.
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Algebra.Com's Answer #814814 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
sample size is 150
\n" ); document.write( "60 are positive for malaria.
\n" ); document.write( "the mean proportion is 60/150 = 6/15 = 2/5 = .4
\n" ); document.write( "the mean proportion standard deviation is sqrt(.4 * .6) / 150) = .04
\n" ); document.write( "critical z-score for 99% two-tailed confidence level is plus or minus 2.5758.\r
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\n" ); document.write( "\n" ); document.write( "the z-score formula is z = (x - m) / s
\n" ); document.write( "z is the z-score.
\n" ); document.write( "x is the sample raw score proportion.
\n" ); document.write( "m is the population mean proportion.
\n" ); document.write( "s is the standard error = sqrt(p*q/n), where:
\n" ); document.write( "p is the population proportion.
\n" ); document.write( "q = 1 - p
\n" ); document.write( "n is the sample size.\r
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\n" ); document.write( "\n" ); document.write( "when z = -2.5758, the formula becomes:
\n" ); document.write( "-2.5758 = (x - .4) / .04
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = -2.5758 * .04 + .4 = .297\r
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\n" ); document.write( "\n" ); document.write( "when z = 2.5758, the formula becomes:
\n" ); document.write( "2.5758 = (x - .4) / .04
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = 2.5758 * .04 + .4 = .503.\r
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\n" ); document.write( "\n" ); document.write( "i believe that's your two-tailed confidence interval.\r
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\n" ); document.write( "\n" ); document.write( "with a sample size of 150, between 30% and 505 will show positive for malaria.\r
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\n" ); document.write( "\n" ); document.write( "that a very high percentage, showing that the population is at high risk for malaria.\r
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\n" ); document.write( "\n" ); document.write( "here's a world malaria report that shows where the highest risks are.\r
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\n" ); document.write( "\n" ); document.write( "https://www.gs.international/learning-centre-articles/malaria-world-map-risk\r
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\n" ); document.write( "\n" ); document.write( "here's a reference on mean proportion and standard deviation.\r
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\n" ); document.write( "\n" ); document.write( "https://stats.libretexts.org/Bookshelves/Introductory_Statistics/Book%3A_Introductory_Statistics_(Shafer_and_Zhang)/06%3A_Sampling_Distributions/6.03%3A_The_Sample_Proportion#:~:text=at%20least%2030.-,The%20Sampling%20Distribution%20of%20the%20Sample%20Proportion,interval%20%5B0%2C1%5D.\r
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\n" ); document.write( "\n" ); document.write( "i'm never 100% certain that i'm right with these types of problems, but i'm reasonably certain that what i gave you is accurate.\r
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