document.write( "Question 1184276: The sum of three numbers is 114. The first number is 6 less than the third. The second number is 4 times the third. What are the numbers? \n" ); document.write( "
Algebra.Com's Answer #814812 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The sum of three numbers is 114. The first number is 6 less than the third. The second number is 4 times the third. What are the numbers?\r
\n" ); document.write( "\n" ); document.write( "let three numbers be \"x\",\"y\", and \"z\" \r
\n" ); document.write( "\n" ); document.write( "if the sum of three numbers is \"114\", we have\r
\n" ); document.write( "\n" ); document.write( "\"x%2By%2Bz=114\".......eq.1\r
\n" ); document.write( "\n" ); document.write( "if the first number is \"6\" less than the third, we have\r
\n" ); document.write( "\n" ); document.write( "\"x=z-6\"....eq.2\r
\n" ); document.write( "\n" ); document.write( "if the second number is \"4\" times the third, we have\r
\n" ); document.write( "\n" ); document.write( "\"y=4z\"....eq.3\r
\n" ); document.write( "\n" ); document.write( "go to\r
\n" ); document.write( "\n" ); document.write( "\"x%2By%2Bz=114\".......eq.1, substitute \"x\" and \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"z-6%2B4z%2Bz=114\"........solve for \"z\"\r
\n" ); document.write( "\n" ); document.write( "\"-6%2B6z=114\".......divide by \"6\"\r
\n" ); document.write( "\n" ); document.write( "\"-1%2Bz=19\"\r
\n" ); document.write( "\n" ); document.write( "\"z=19%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"z=20\"\r
\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( "\"x=20-6\"
\n" ); document.write( "\"x=14\"\r
\n" ); document.write( "\n" ); document.write( "and
\n" ); document.write( "\"y=4%2A20\"
\n" ); document.write( "\"y=80\"\r
\n" ); document.write( "\n" ); document.write( "so, your numbers are: \"14\",\"80\", and \"20\"\r
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