document.write( "Question 111555: Raising rabbits. Before Roland sold two female rabbits, half of his rabbits were female. After the sale, only one-third of his rabbits were female. If x represents his original number of rabbits, then \r
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document.write( "1/2x-2=1/3(x-2)
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Algebra.Com's Answer #81477 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! x=original number of rabbits\r \n" ); document.write( "\n" ); document.write( "Then x/2=original number of female rabbits \n" ); document.write( "and x/2=original number of male rabbits\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "After he sells two female rabbits, he has 1/3(x-2) female rabbits left\r \n" ); document.write( "\n" ); document.write( "So, the way I see it is as follows:\r \n" ); document.write( "\n" ); document.write( "Number of female rabbits after the sale {(1/3)(x-2)} plus the number of male rabbits (x/2) equals the original number of rabbits less 2 (the females that he sold):\r \n" ); document.write( "\n" ); document.write( "1/3(x-2)+(x/2)=x-2 simplify\r \n" ); document.write( "\n" ); document.write( "(1/3)x-(2/3)+(x/2)=x-2 multiply each term by 6\r \n" ); document.write( "\n" ); document.write( "2x-4+3x=6x-12 simplify \n" ); document.write( "5x-4=6x-12 subtract 6x from and add 4 to both sides\r \n" ); document.write( "\n" ); document.write( "5x-6x-4+4=6x-6x-12+4 \n" ); document.write( "-x=-8 multiply each term by -1\r \n" ); document.write( "\n" ); document.write( "x=8 original number of rabbits\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "Original number of females=x/2=8/2=4 \n" ); document.write( "Give away 2, then Roland has 2 females left and 4 males left for a total of 6 rabbits and 1/3 of them, or 2, are females.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " \n" ); document.write( " |