document.write( "Question 111555: Raising rabbits. Before Roland sold two female rabbits, half of his rabbits were female. After the sale, only one-third of his rabbits were female. If x represents his original number of rabbits, then \r
\n" ); document.write( "\n" ); document.write( "1/2x-2=1/3(x-2)
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #81477 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
x=original number of rabbits\r
\n" ); document.write( "\n" ); document.write( "Then x/2=original number of female rabbits
\n" ); document.write( "and x/2=original number of male rabbits\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "After he sells two female rabbits, he has 1/3(x-2) female rabbits left\r
\n" ); document.write( "\n" ); document.write( "So, the way I see it is as follows:\r
\n" ); document.write( "\n" ); document.write( "Number of female rabbits after the sale {(1/3)(x-2)} plus the number of male rabbits (x/2) equals the original number of rabbits less 2 (the females that he sold):\r
\n" ); document.write( "\n" ); document.write( "1/3(x-2)+(x/2)=x-2 simplify\r
\n" ); document.write( "\n" ); document.write( "(1/3)x-(2/3)+(x/2)=x-2 multiply each term by 6\r
\n" ); document.write( "\n" ); document.write( "2x-4+3x=6x-12 simplify
\n" ); document.write( "5x-4=6x-12 subtract 6x from and add 4 to both sides\r
\n" ); document.write( "\n" ); document.write( "5x-6x-4+4=6x-6x-12+4
\n" ); document.write( "-x=-8 multiply each term by -1\r
\n" ); document.write( "\n" ); document.write( "x=8 original number of rabbits\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "Original number of females=x/2=8/2=4
\n" ); document.write( "Give away 2, then Roland has 2 females left and 4 males left for a total of 6 rabbits and 1/3 of them, or 2, are females.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
\n" ); document.write( "
\n" ); document.write( "
\n" );