document.write( "Question 1184223: Four speakers P, Q, R and S will address the meeting with the condition that speaker Q will speak after speaker S. Find the number of ways in which the order of speakers can be prepared? \n" ); document.write( "
Algebra.Com's Answer #814753 by ikleyn(52835)\"\" \"About 
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document.write( "In this problem, instead of 4 objects, we consider 4-1 = 3 objects,\r\n" );
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document.write( "looking at the pair SQ as one unit.\r\n" );
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document.write( "For 3 objects, we have 3! = 6 possible permutations;\r\n" );
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document.write( "therefore, the answer to the problem's question is  3! = 6.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Hello,  the previous solution was done assuming that speaker  Q  addresses  IMMEDIATELY  after speaker  S.\r
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\n" ); document.write( "\n" ); document.write( "If the problem means  \" after,  but not necessary immediately after \",  then the answer is   \"%281%2F2%29%2A4%21\" = \"24%2F2\" = 12:\r
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\n" ); document.write( "\n" ); document.write( "In half of  4! = 24 permutations,  Q  follows  S;  in other half of permutations,  S  follows  Q.\r
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