document.write( "Question 1184217: If \"+%28z-1%29%2F%28z%2B1%29+\" is purely imaginary then what is value of |z|? \n" ); document.write( "
Algebra.Com's Answer #814744 by robertb(5830)\"\" \"About 
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If \"+%28z-1%29%2F%28z%2B1%29+\" is purely imaginary, then \"+%28z-1%29%2F%28z%2B1%29+=+Ai\" for some \"A%3C%3E0\".\r
\n" ); document.write( "\n" ); document.write( "Let z = a + bi.
\n" ); document.write( "===> z - 1 = A(z+1)i ===> a + bi - 1 = A(a + bi + 1)i\r
\n" ); document.write( "\n" ); document.write( "===> a + bi - 1 = A((a + 1)i - b) = A(a+1)i - Ab\r
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\n" ); document.write( "\n" ); document.write( "<===> (a - 1 + Ab) + (b - A(a+1))i = 0\r
\n" ); document.write( "\n" ); document.write( "===> a - 1 + Ab = 0 and b - A(a+1) = 0, or \r
\n" ); document.write( "\n" ); document.write( "===> a + Ab = 1 and -Aa + b = A.\r
\n" ); document.write( "\n" ); document.write( "===> \"a+=+%281-A%5E2%29%2F%281%2BA%5E2%29\" and \"b+=+%282A%29%2F%281%2BA%5E2%29\" after solving the system for a and b.\r
\n" ); document.write( "\n" ); document.write( "===> \"z++=+a%2Bbi+=++%281-A%5E2%29%2F%281%2BA%5E2%29+%2B+i%2A%28%282A%29%2F%281%2BA%5E2%29%29\"\r
\n" ); document.write( "\n" ); document.write( "===> \r
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\n" ); document.write( "\n" ); document.write( "=\r
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\n" ); document.write( "\n" ); document.write( "Therefore, \"highlight%28abs%28z%29+=+1%29\"\r
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