document.write( "Question 1184148: 0 breaks 1 breaks 2 breaks
\n" ); document.write( "0 defects 0.1 0.1 0.25
\n" ); document.write( "1 defects 0.15 0.18 0.02
\n" ); document.write( "2 defects 0.05 0.12 0.03\r
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\n" ); document.write( "\n" ); document.write( "At my tiny factory, each worker produces mini erasers. In a given day, workers produce D = 0, 1, or 2 defects and take B = 0, 1, or 2 bathroom breaks. The joint probability distribution is above. \r
\n" ); document.write( "\n" ); document.write( "If a worker takes 0 bathroom breaks, what is the expected number of defects? That is, what is E[D|B = 0]?\r
\n" ); document.write( "\n" ); document.write( "Your answer should be between 0 and 1. Round your answer to two decimal places, if necessary
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Algebra.Com's Answer #814723 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "P(D = 0|B = 0) = \"0.1%2F%283%2F10%29++=+1%2F3\"
\n" ); document.write( "P(D = 1|B = 0) = \"0.15%2F%283%2F10%29++=+1%2F2\"
\n" ); document.write( "P(D = 2|B = 0) = \"0.05%2F%283%2F10%29++=+1%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "===> E[D| B = 0] = \"0%2A%281%2F3%29+%2B+1%2A%281%2F2%29+%2B+2%2A%281%2F6%29+=+highlight%285%2F6%29\".
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