document.write( "Question 1184175: how many quarts of pure antifreeze must be added to 4 quarts of a 50% antifreeze solution to obtain a 60% antifreeze solution? (hint: pure antifreeze is 100% antifreeze) round to nearest tenth as needed. \n" ); document.write( "
Algebra.Com's Answer #814719 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The response from the other tutor is not much help to a student who is trying to learn HOW to set up and solve this kind of problem....

\n" ); document.write( "Let x be the number of quarts of 100% antifreeze to add.

\n" ); document.write( "The antifreeze in the two ingredients is 100% of x quarts, plus 50% of the 4 quarts you started with; and it is 60% of the total (x+4) quarts:

\n" ); document.write( "\"100%28x%29%2B50%284%29=60%28x%2B4%29\"

\n" ); document.write( "Solve using basic algebra... I leave that to you.

\n" ); document.write( "If a formal algebraic solution is not required, here is a quick and easy way to solve any 2-part \"mixture\" problem like this.

\n" ); document.write( "Picture the percentages of the two ingredients and the final mixture on a number line -- 50, 60, and 100; observe/calculate that 60% is 1/5 of the way from 50% to 100%. (50 to 100 is a difference of 50; 50 to 60 is a difference of 10; 10/50 = 1/5.)

\n" ); document.write( "That means 1/5 of the mixture is the 100% antifreeze that you are adding.

\n" ); document.write( "So the 4 quarts you started with is 4/5 of the mixture; that means the 1/5 of the mixture that you added is 1 quart.

\n" ); document.write( "ANSWER: add 1 quart of 100% antifreeze

\n" ); document.write( "CHECK:
\n" ); document.write( ".50(4)+1.00(1)=2+1=3
\n" ); document.write( ".60(5)=3

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