document.write( "Question 1184175: how many quarts of pure antifreeze must be added to 4 quarts of a 50% antifreeze solution to obtain a 60% antifreeze solution? (hint: pure antifreeze is 100% antifreeze) round to nearest tenth as needed. \n" ); document.write( "
Algebra.Com's Answer #814719 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The response from the other tutor is not much help to a student who is trying to learn HOW to set up and solve this kind of problem.... \n" ); document.write( "Let x be the number of quarts of 100% antifreeze to add. \n" ); document.write( "The antifreeze in the two ingredients is 100% of x quarts, plus 50% of the 4 quarts you started with; and it is 60% of the total (x+4) quarts: \n" ); document.write( " \n" ); document.write( "Solve using basic algebra... I leave that to you. \n" ); document.write( "If a formal algebraic solution is not required, here is a quick and easy way to solve any 2-part \"mixture\" problem like this. \n" ); document.write( "Picture the percentages of the two ingredients and the final mixture on a number line -- 50, 60, and 100; observe/calculate that 60% is 1/5 of the way from 50% to 100%. (50 to 100 is a difference of 50; 50 to 60 is a difference of 10; 10/50 = 1/5.) \n" ); document.write( "That means 1/5 of the mixture is the 100% antifreeze that you are adding. \n" ); document.write( "So the 4 quarts you started with is 4/5 of the mixture; that means the 1/5 of the mixture that you added is 1 quart. \n" ); document.write( "ANSWER: add 1 quart of 100% antifreeze \n" ); document.write( "CHECK: \n" ); document.write( ".50(4)+1.00(1)=2+1=3 \n" ); document.write( ".60(5)=3 \n" ); document.write( " \n" ); document.write( " |