document.write( "Question 1184170: Let a, b, c be three sides opposite to the angles A, B, C respectively in a triangle ABC. Find 2ac.Sin(A + C - B)/2? \n" );
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Algebra.Com's Answer #814705 by ikleyn(52834)  You can put this solution on YOUR website! . \n" );
document.write( "Let a, b, c be three sides opposite to the angles A, B, C respectively in a triangle ABC. \n" );
document.write( "Find 2ac.Sin((A + C - B)/2). \n" );
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document.write( "First, = = = .\r\n" );
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document.write( "THEREFORE, = = cos(B).\r\n" );
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document.write( "Next, due to the cosine law for triangle ABC\r\n" );
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document.write( " = + - .\r\n" );
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document.write( "It implies\r\n" );
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document.write( " 2ac*cos(B) = a^2 + c^2 - b^2\r\n" );
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document.write( "Now we can write the final identity\r\n" );
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document.write( " = 2ac*cos(B) = .\r\n" );
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document.write( "ANSWER. = .\r\n" );
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document.write( "Solved.\r \n" );
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