document.write( "Question 1184071: A bank loaned out $9,000, part of it at the rate of 12% annual interest, and the rest at 14% annual interest. The total interest earned for both loans was $1,110.00. How much was loaned at each rate? \n" ); document.write( "
Algebra.Com's Answer #814677 by Theo(13342)\"\" \"About 
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let A = amount invested at 12%.
\n" ); document.write( "let B = amount invested at 14%.\r
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\n" ); document.write( "\n" ); document.write( "your two equations that need to be solved simultaneously are:\r
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\n" ); document.write( "\n" ); document.write( "A + B = 9000
\n" ); document.write( ".12A + .14B = 1110\r
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\n" ); document.write( "\n" ); document.write( "multiply both sides of the first equation by .12 and leave the second equation as is to get:\r
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\n" ); document.write( "\n" ); document.write( ".12A + .12B = 1080
\n" ); document.write( ".12A + .14B = 1110\r
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\n" ); document.write( "\n" ); document.write( "subtract the first equation from the second to get:\r
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\n" ); document.write( "\n" ); document.write( ".02B = 30\r
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\n" ); document.write( "\n" ); document.write( "solve for B to get:\r
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\n" ); document.write( "\n" ); document.write( "B = 30/.02 = 1500\r
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\n" ); document.write( "\n" ); document.write( "since A + B = 9000, then A must be equal to 9000 - 1500 = 7500\r
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\n" ); document.write( "\n" ); document.write( "A + B = 9000 becomes 7500 + 1500 = 9000 which is true.
\n" ); document.write( ".12A + .14B = 1110 becomes 900 + 210 = 1110 which is also true.\r
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\n" ); document.write( "\n" ); document.write( "the solution is confirmed to be good.\r
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\n" ); document.write( "\n" ); document.write( "the solution is that 7500 was loaned at 12% and 1500 was loaned at 14%.\r
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