document.write( "Question 111690: The length of a rectangular garden is 5 feet longer than the width. The garden is surrounded by a 2 foot wide sidewalk. The sidewalk has an area of 76 square feet. Find the dimensions of the garden. \n" ); document.write( "
Algebra.Com's Answer #81467 by edjones(8007)\"\" \"About 
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L=w+5 (garden)
\n" ); document.write( "L*w=A
\n" ); document.write( "w*(w+5)=w^2+5w (area of garden)
\n" ); document.write( "(w+4)*(w+5+4)=76+w^2+5w (area of garden plus sidewalk)
\n" ); document.write( "(w+4)*(w+9)=76+w^2+5w
\n" ); document.write( "w^2+13w+36=w^2+5w+76
\n" ); document.write( "8w=40 subtract w^2+5w+36 from each side.
\n" ); document.write( "w=5
\n" ); document.write( "L=5+5=10
\n" ); document.write( "Check
\n" ); document.write( "(5+4)*(10+4)=126
\n" ); document.write( "126-50=76
\n" ); document.write( "Ed
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