document.write( "Question 111690: The length of a rectangular garden is 5 feet longer than the width. The garden is surrounded by a 2 foot wide sidewalk. The sidewalk has an area of 76 square feet. Find the dimensions of the garden. \n" ); document.write( "
Algebra.Com's Answer #81464 by malakumar_kos@yahoo.com(315)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangular garden is 5 feet longer than the width. The garden is surrounded by a 2 foot wide sidewalk. The sidewalk has an area of 76 square feet. Find the dimensions of the garden. \r \n" ); document.write( "\n" ); document.write( " let the width of the garden be = x ft\r \n" ); document.write( "\n" ); document.write( " then length of the garden will be = (x+5) ft\r \n" ); document.write( "\n" ); document.write( " Area of the garden = x(x+5) sqft\r \n" ); document.write( "\n" ); document.write( " After including the measure of side walk on width &length we get the new \r \n" ); document.write( "\n" ); document.write( " width & length of the entire garden as, width = (x+4) ft and \r \n" ); document.write( "\n" ); document.write( " length = ((5+x+4) = (9+x) ft\r \n" ); document.write( "\n" ); document.write( " Area of the side walk = Area of the entire garden - Area of the garden excluding the side walk\r \n" ); document.write( "\n" ); document.write( " i,e 76 = (x+4)(x+9) - x(x+5)\r \n" ); document.write( "\n" ); document.write( " 76 = x^2+13x+36-x^2-5x\r \n" ); document.write( "\n" ); document.write( " 76-36 = 13x-5x \n" ); document.write( " 40 = 8x => x = 40/8 = 5 ft\r \n" ); document.write( "\n" ); document.write( " dimensions of the garden is width = 5 ft and length = (5+5) = 10 ft \n" ); document.write( " |