document.write( "Question 1184101: Suppose that one solution contains 30% alcohol and another solution contains
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document.write( "80% alcohol. How many liters of each solution should be mixed to make 12.5
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document.write( "liters of a 60% alcohol solution? \n" );
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Algebra.Com's Answer #814632 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Using the standard formal algebraic solution method.... \n" ); document.write( "x = liters of 30% alcohol \n" ); document.write( "12.5-x = liters of 80% alcohol \n" ); document.write( "The total amount of alcohol in the two ingredients is 60% of the total 12.5 liters: \n" ); document.write( " \n" ); document.write( "I'll let you finish the solution by that method.... \n" ); document.write( "Here is a quick and easy way to solve any 2-part \"mixture\" problem like this if a formal algebraic solution is not required.... \n" ); document.write( "Consider the three percentages 30, 60, and 80 on a number line and observe/calculate that 60 is 3/5 of the way from 30 to 80. (30 to 80 is a difference of 50, 30 to 60 is a difference of 30; 30/50 = 3/5.) \n" ); document.write( "That means 3/5 of the mixture is the 80% alcohol. \n" ); document.write( "ANSWER: 3/5 of 12.5 liters, or 7.5 liters, of 80% alcohol; the other 5 liters of 30% alcohol. \n" ); document.write( "CHECK: \n" ); document.write( ".80(7.5)+.30(5)=6+1.5=7.5 \n" ); document.write( ".60(12.5)=7.5 \n" ); document.write( " \n" ); document.write( " |