document.write( "Question 1184102: Doris invested some money at 6% and some money at 7%. She invested $6,000 more at 7% than she did at 6%. Her total yearly interest from the two investments was $680. How much did Doris invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #814629 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "x = amount invested at 6%
\n" ); document.write( "x+6000 = amount invested at 7%

\n" ); document.write( "Total interest was $680:

\n" ); document.write( "\".06%28x%29%2B.07%28x%2B6000%29=680\"

\n" ); document.write( "I personally would multiply by 100 to get rid of the decimals...

\n" ); document.write( "\"6x%2B7%28x%2B6000%29=68000\"

\n" ); document.write( "You can finish from there....

\n" ); document.write( "(final answers: $2000 at 6%, $8000 at 7%)

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