document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1184074>Question 1184074</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The resistance, R, of a wire varies directly as its length and inversely as the square of its diameter.  If the resistance of a wire 4000ft long with a diameter of 0.18 inches is 7867 ohms, what is the resistance of 4300ft of the same type of wire with a diameter of 0.27 inches?  (Leave k in fraction form or round to at least 3 decimal places.  Round off your final answer to the nearest hundredth.)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #814615 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=814615\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The post implies that we are supposed to find the constant of variation k; but there is no need to do so.<br><BR>\n" );
document.write( "Changing the length from 4000ft to 4300ft increases the resistance by a factor of 4300/4000 = 43/40.<br><BR>\n" );
document.write( "Changing the diameter from 0.18 inches to 0.27 inches decreases the resistance by a factor of (.27/.18)^2 = (3/2)^2 = 9/4.<br><BR>\n" );
document.write( "ANSWER: 7867*(43/40)/(9/4) = 7867*(43/40)*(4/9) = 3758.677777... = 3758.68 to the nearest hundredth.<br><BR>\n" );
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