document.write( "Question 111663: I need help solving and check for extraneous solutions:\r
\n" ); document.write( "\n" ); document.write( "√y+9=1
\n" ); document.write( "

Algebra.Com's Answer #81459 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve and check for extraneous roots.
\n" ); document.write( "\"sqrt%28y%2B9%29+=+1\" Square both sides. This might introduce extraneous roots.
\n" ); document.write( "\"y%2B9+=+1\" or \"y%2B9+=+-1\" Subtract 9 from both sides in both of these.
\n" ); document.write( "\"y+=+-8\" or \"y+=+-10\"
\n" ); document.write( "Check solutions:
\n" ); document.write( "\"sqrt%28y%2B9%29+=+1\" Substitute y = -8.
\n" ); document.write( "\"sqrt%28-8%2B9%29+=+1\"
\n" ); document.write( "\"sqrt%281%29+=+1\" Ok
\n" ); document.write( "\"sqrt%28y%2B9%29+=+1\" Substitute y = -10
\n" ); document.write( "\"sqrt%28-10%2B9%29+=+1\"
\n" ); document.write( "\"sqrt%28-1%29+=+1\" Not valid! This is an extraneous root.
\n" ); document.write( "
\n" ); document.write( "
\n" );