document.write( "Question 1184038: 2 unequal jugs are filled with diluted cordial with different concentrations. The
\n" ); document.write( "first jug has cordial and water in the ratio 2:5 and the second jug has cordial and
\n" ); document.write( "water in the ratio 3:7. The contents of the two jugs are then combined.
\n" ); document.write( "If the second jug had twice the volume of diluted cordial compared to the first,
\n" ); document.write( "what is the ratio of cordial to water in the final mixture? \n" ); document.write( "

Algebra.Com's Answer #814577 by ikleyn(52778) $\"\"$ $\"About$

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\n" ); document.write( "2 unequal jugs are filled with diluted cordial with different concentrations. The
\n" ); document.write( "first jug has cordial and water in the ratio 2:5 and the second jug has cordial and
\n" ); document.write( "water in the ratio 3:7. The contents of the two jugs are then combined.
\n" ); document.write( "If the second jug had twice the volume of diluted cordial compared to the first,
\n" ); document.write( "what is the ratio of cordial to water in the final mixture?
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document.write( "Let's calibrate the volumes in both jugs ADEQUATELY.\r\n" );
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document.write( "First  jug has the volume of cordial 2x per water volume of 5x.\r\n" );
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document.write( "Second jug has the volume of cordial 3y per water volume of 7y.\r\n" );
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document.write( "Here x and y are commonn measures of volumes for liquids in the 1st and the 2nd jugs, respectively.\r\n" );
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document.write( "        According to the condition,  3y = 2(2x),  or  3y = 4x,  i.e.  y = .\r\n" );
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document.write( "So, we can say that 1st jug has the volume of cordial  2x  per water volume of  5x,  while\r\n" );
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document.write( "                    2nd jug has the volume of cordial  3y=4x  per water volume 7y =  = .\r\n" );
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document.write( "Now, in the mixture we have the cordial volume of  2x + 4x = 6x\r\n" );
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document.write( "per water volume of  5x +  =  = .\r\n" );
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document.write( "The ratio of cordial to water in the final mixture is   =  = .    ANSWER\r\n" );
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